[SOLVED] How to sed the "\\" in variable in bash

Issue

The following bash is used to replace the "$source_product" with "$source_product" + "linefeed" + "$target_product".

Here is the bash script:

source_product="\$(LOCAL_DIR)/source \\"
target_product="\$(LOCAL_DIR)/target \\"

echo "source_product: $source_product"
echo "target_product: $target_product"
echo ""
echo "--- replace source with source+target ---"
echo ""

sed "s|${source_product}|${source_product}\n${target_product}|g" <<< "${source_product}"

Here is the output:

source_product: $(LOCAL_DIR)/source \
target_product: $(LOCAL_DIR)/target \

--- replace source with source+target ---

sed: -e expression #1, char 70: unterminated `s' command

Here is the expected output:

source_product: $(LOCAL_DIR)/source \
target_product: $(LOCAL_DIR)/target \

--- replace source with source+target ---

$(LOCAL_DIR)/source \
$(LOCAL_DIR)/target \

What's wrong in the above "sed"? And how to fix?

Update:

Here is the file contains the "$(LOCAL_DIR)/source \", I want to add the "$(LOCAL_DIR)/target \" just below the "$(LOCAL_DIR)/source \":

...
other format a
...
$(LOCAL_DIR)/product_foo \
$(LOCAL_DIR)/bar \
$(LOCAL_DIR)/hello \
$(LOCAL_DIR)/world \
$(LOCAL_DIR)/source \
$(LOCAL_DIR)/others_1 \
$(LOCAL_DIR)/others_2 \
$(LOCAL_DIR)/many_other_products \
...
other format b
...

I think sed is the best solution.

Solution

You need to escape the backslashes (with more backslashes). You can do this using Bash substitution directly in your sed command:

sed "s|${source_product//\\/\\\\}|${source_product//\\/\\\\}\n${target_product//\\/\\\\}|g" <<< "${source_product}"

Answered By - jmd_dk

Answer Checked By - Dawn Plyler (WPSolving Volunteer)