[SOLVED] How to store .txt file data in different columns of a CSV file using BASH?

Issue

I have a .txt file with the following data structure:

Scan Times:
 33.3 seconds
 77.4 seconds
 33.3 seconds
 77.4 seconds

Check Times:
 110.30 seconds
 72.99 seconds
 72.16 seconds
 110.30 seconds

Move Times:
 73.66 seconds
 90.77 seconds
 72.87 seconds
 71.75 seconds
 
Switch Times:
 92.0 seconds
 78.6 seconds
 77.8 seconds
 84.9 seconds

I now want to take that .txt file and create a CSV file that has the following format.

I have a very basic layout so far with my bash script but I am not sure how to proceed:

inputFiles=("./Successes/SuccessSummary.txt" "./Failures/FailSummary.txt")
touch results.csv

for file in "${inputFiles[@]}"
do 
    while IFS= read -r line
    do
        #echo $line
        if [ "$line" = "Scan Times:" ]
        then 
        fi

        if [ "$line" = "Check Times:" ]
        then 
        fi

        if [ "$line" = "Move Times:" ]
        then 
        fi
        
        if [ "$line" = "Switch Distances:" ]
        then 
        fi
    done < "$file"
done

Solution

Here's an awk script that does it:

#!/usr/bin/awk -f

BEGIN {
    OFS=","
    colnum=0
}

/:$/ {
    data[++colnum,1]=$0
    rownum=1
}

/seconds$/ {
    data[colnum,++rownum]=$1
}

END {
    for (r = 1; r <= rownum; r++) {
        for (c = 1; c <= colnum; c++) {
            printf "%s%s", data[c,r], (c == colnum ? RS : OFS)
        }
    }
}

Example:

$ ./pivot input.txt
Scan Times:,Check Times:,Move Times:,Switch Times:
33.3,110.30,73.66,92.0
77.4,72.99,90.77,78.6
33.3,72.16,72.87,77.8
77.4,110.30,71.75,84.9

Answered By - Shawn