[SOLVED] Unix sed command to find and replace a pattern

Issue

I am trying to match the below pattern which has spaces in between.

         -DsomeArg=some value 

and to replace it with below pattern using sed command.

         -DsomeArg="some value"

There can be any number of spaces in between. I tried below command but it's not working.

          sed 's/^\(-D.*\)=(.\+\s\+.\+)/\1="\2"/' test.dat

where as .* works instead of .+ , but I want to match one or more pattern. I am not able to find what I am doing wrong.

Solution

cat /tmp/test | sed -r 's/^(-D.*?)=(.+\s+.+)/\1="\2"/'
-DsomeArg="some value"

Hope that will help :)

Answered By - Adam Sznajder