[SOLVED] version and pkgname extraction

Issue

I've the following variables in bash script.

xyz-0.3.2-3
abc-xyz-tools-0.1-1
def-yz-7.3.0-1.0.0

Result should be for :

pkg: xyz and version of xyz : 0.3.2-3
pkg: abc-xyz-tools version of abc-xzy-tools: 0.1-1
pkg: def-yz version of def-yz: 7.3.0-1.0.0

Since the pkg names are of different word length and versions are of different lengths, it's slightly tricky.

Your help will be appreciated. (bash,sed,awk would be preferred lang)

Solution

EDIT: With package name code.

awk --re-interval '
match($0,/([a-zA-Z]+\-+){1,}/){
  val=substr($0,RSTART,RLENGTH-1);
  print "pkg: " val " and version of " val " : " substr($0,RSTART+RLENGTH)
}'  Input_file

Could you please try following awk and let me know if this helps you.(remove --re-interval in case you have newer version of awk with you).

awk --re-interval 'match($0,/([a-zA-Z]+\-+){1,}/){print substr($0,RSTART+RLENGTH)}' Input_file

Answered By - RavinderSingh13