[SOLVED] get status code as output from Apache "access" log file format

Issue

127.0.0.1 - frank [10/Oct/2000:13:55:36 -0700] "GET /apache_pb.gif HTTP/1.0" 200 2326 

How do i output the status code using the above code snippet, I tried using the cut command but there seems to be some problem

Solution

If you use awk you can do one of two things: if you assume the status is always the 9th field (remember it tokenizes using spaces by default)

  awk '{print $9}' 

or if you assume it is always the second to last field (as @anubhave mentioned in comments):

  awk '{print $(NF-1)}'

If you prefer sed

  sed -n  's/.*GET [^ ]* HTTP[^ ]*" \([0-9]\{3\}\) .*/\1/p'

Answered By - Rob