[SOLVED] How to use grep to output result of each line?

Issue

I have a text file with a random number of lines. Lines look like this:

neededLine [text1] sometext [text2] sometext [text3]
sometext [text4] sometext [text5] sometext [text6]
neededLine [text7] sometext [text8] sometext [text9]

I have a grep command in shell, which takes lines with 'neededLine' word, and then extracts everything inside brackets. Command looks like this: grep 'neededLine' |grep -Po '(?<=\[).*?(?=\])' | tr '\n' ' '

So my output looks like this:

text1 text2 text3 text7 text8 text9

If I remove tr, output starts with a new line for every single word:

text1 
text2 
text3
...

How do I get an output, which prints the result in one separate line for every single input line? It should look like

text1 text2 text3 
text7 text8 text9

Solution

With sed:

sed '/neededLine/!d
s/[^[]*\[//
s/\][^[]*$//
s/\][^[]*\[/ /g' file

Answered By - oguz ismail