[SOLVED] grep count all matches in one line of single pattern

Issue

How can I count all matches with grep, when there are more than one match per line?

$ cat example.txt
int foo(int a, char b) { int i = 80; return i; }
$ grep -c "int" example.txt
1

I want to output 3 (since int appears 3 times in the file)

Solution

With grep that supports -o option:

$ grep -o 'int' ip.txt | wc -l
3

With ripgrep:

$ rg -oc 'int' ip.txt
3

Answered By - Sundeep