Issue
When is it necessary to use use the flag -stdlib=libstdc++
for the compiler and linker when compiling with gcc?
Does the compiler automatically use libstdc++?
I am using gcc4.8.2 on Ubuntu 13.10 and I would like to use the c++11 standard. I already pass -std=c++11
to the compiler.
Solution
On Linux: In general, all commonly available linux distributions will use libstdc++ by default, and all modern versions of GCC come with a libstdc++ that supports C++11. If you want to compile c++11 code here, use one of:
g++ -std=c++11 input.cxx -o a.out
(usually GNU compiler)g++ -std=gnu++11 input.cxx -o a.out
On OS X before Mavericks: g++
was actually an alias for clang++
and Apple's old version of libstdc++ was the default. You could use libc++ (which included c++11 library support) by passing -stdlib=libc++
. If you want to compile c++11 code here, use one of:
g++ -std=c++11 -stdlib=libc++ input.cxx -o a.out
(clang, not GNU compiler!)g++ -std=gnu++11 -stdlib=libc++ input.cxx -o a.out
(clang, not GNU compiler!)clang++ -std=c++11 -stdlib=libc++ input.cxx -o a.out
clang++ -std=gnu++11 -stdlib=libc++ input.cxx -o a.out
On OS X since Mavericks: libc++ is the default and you should not pass any -stdlib=<...>
flag. Since Xcode 10, building against libstdc++ is not supported at all anymore. Existing code built against libstdc++ will keep working because libstdc++.6.dylib
is still provided, but compiling new code against libstdc++ is not supported.
clang++ -std=c++11 input.cxx -o a.out
clang++ -std=gnu++11 input.cxx -o a.out
Answered By - Bill Lynch