[SOLVED] AWK print if found three matches, one false

Issue

There is several lines in a file that looks like:

A   B   C   H
A   B   C   D

and, I want to print all lines that contain this RE:

/A\tB/

But, if the line contain and H in the fourth field, do not print, the output would be:

A   B   C   D

It could be written in one line in sed, awk or grep?

The only thing that I know is:

awk '/^A\tB/'

Solution

With awk one-liner:

awk -F'\t' '$1=="A" && $2=="B" && $4!="H"' file

• -F'\t' - tab char \t is treated as field separator

The output:

A   B   C   D

Answered By - RomanPerekhrest

Answer Checked By - Dawn Plyler (WPSolving Volunteer)