[SOLVED] How to remove | substract directory name from bash?

Issue

Given

DIRNAME_MAIN="/home/vMX-ENV/vMX-21.1R1/"

I would like to ONLY display 21.1R1 from the directory above, Is there any way I can only display value after home/vMX-ENV/vMX-?? and remove the / at the end so instead of being 21.1R1/ it will end up being: 21.1R1?

Thanks!

Solution

Using sed grouping and back referencing

$ sed 's/[^0-9]*\([^/]*\).*/\1/' input_file
21.1R1

/[^0-9]* - Exclude anything up to the next occurance of a digit character. As this part is not within the parenthesis () to be grouped, it will be excluded.

\([^/]*\) - This will group everything from the first digit up to the next occurance of / slash.

.*/ - Exclude everything else

\1 - Return the group with backreference \1.

awk can also be used.

$ awk -F"[/-]" '{print $6}' input_file
21.1R1

-F"[/-]" - Set delimiter to / and - then print column 6 which will contain the string.

Answered By - HatLess

Answer Checked By - Pedro (WPSolving Volunteer)