Issue

I am confused about a bash script.

I have the following code:

function grep_search() {
    magic_way_to_define_magic_variable_$1=`ls | tail -1`
    echo $magic_variable_$1
}

I want to be able to create a variable name containing the first argument of the command and bearing the value of e.g. the last line of ls.

So to illustrate what I want:

$ ls | tail -1
stack-overflow.txt

$ grep_search() open_box
stack-overflow.txt

So, how should I define/declare $magic_way_to_define_magic_variable_$1 and how should I call it within the script?

I have tried eval, ${...}, \$${...}, but I am still confused.

Solution

Use an associative array, with command names as keys.

# Requires bash 4, though
declare -A magic_variable=()

function grep_search() {
    magic_variable[$1]=$( ls | tail -1 )
    echo ${magic_variable[$1]}
}

If you can't use associative arrays (e.g., you must support bash 3), you can use declare to create dynamic variable names:

declare "magic_variable_$1=$(ls | tail -1)"

and use indirect parameter expansion to access the value.

var="magic_variable_$1"
echo "${!var}"

See BashFAQ: Indirection - Evaluating indirect/reference variables.

Answered By - chepner

Answer Checked By - Clifford M. (WPSolving Volunteer)

Thursday, March 17, 2022

[SOLVED] Dynamic variable names in Bash

Issue

Solution