[SOLVED] How To Generate a Random Number that is a multiple 3 in a Range in a Bash Script?

Issue

I apologize if my title question is too broad. I am trying to generate a variable that is a random multiple of 3 between a certain range.

randomNumber= Multiple of 3 between 45 and 72

Solution

Bash has a builtin RANDOM ^{(0 ~ 32767)} var. If you have Bash 5.1+, there's also SRANDOM ^{(0 ~ 4294967295)}.

[Bash-5.2] % echo $(( 3 * (15 + RANDOM % 10) ))
51
[Bash-5.2] % echo $(( 3 * (15 + RANDOM % 10) ))
57
[Bash-5.2] % echo $(( 3 * (15 + RANDOM % 10) ))
48

Answered By - pynexj

Answer Checked By - Robin (WPSolving Admin)