[SOLVED] How can I make this bash code remove the decimal places?

Issue

free | grep Mem | awk '{print $4/$2 * 100.0}'

I want to remove the decimal places from this output.

Solution

free | grep Mem | awk '{print $4/$2 * 100.0}' | cut -d. -f1

or

free | grep Mem | awk '{print int($4/$2 * 100.0)}'

Answered By - robobrobro

Answer Checked By - Senaida (WPSolving Volunteer)