[SOLVED] How to add single quote to only word which has dot in the middle (or anywhere except begining) of the word using sed/awk on MAC (no gnu support)?

Issue

Part of input file with many lines:

.class xyz.com class.name_1 and xxx.co .class class.man_3 'abc.name_4' #id
#id .class abc.name class.name and class.name_2 class.name_3 .class class.dragon class.xyz 

Desire Output:

.class 'xyz.com' 'class.name_1' and 'xxx.co' .class 'class.man_3' 'abc.name_4' #id
#id .class 'abc.name' 'class.name' and 'class.name_2' 'class.name_3' .class 'class.dragon' 'class.xyz' 

should handle this input as well:

.xxx-xxxx.xxxx-xxxx 
.xxxx.xxxx
xic.aco-eiopw-ejek.cojdj

output

.xxx-xxxx.xxxx-xxxx 
.xxxx.xxxx
'xic.aco-eiopw-ejek.cojdj'

I tried using this sed "s/^\(.* \)\(.*\.\)\(.* \)/\'1\2\3'/g" It gives following output:

'1class.name_4 #id '
'1class.name_4 '
....

Solution

Here is an awk version

awk -v s="'" '!/^#/{for(i=1;i<=NF;i++) if($i~"^[^.].*[.]" && $i!~"^"s) $i=s$i s}1' file
.class 'xyz.com' 'class.name_1' and 'xxx.co' .class 'class.man_3' 'abc.name_4' #id
#id .class abc.name class.name and class.name_2 class.name_3 .class class.dragon class.xyz

s="'" # set s to singe quote (simpler to handle this way)
!/^#/ # run next part only if line does not start with #
{for(i=1;i<=NF;i++) # Loop trough all fields on the line
if($i~"^[^.].*[.]" # Test if field has an dot, but not as first character
&& $i!~"^"s # And it also does not start with single quote (the value of s)
$i=s$i s # Add single quote on both side of field
1 # print the line (always true)

Answered By - Jotne

Answer Checked By - Candace Johnson (WPSolving Volunteer)