Issue
I am having trouble matching specific column with grep command. I have a test file (test.txt) like this..
Bra001325 835 T 13 c$c$c$c$c$cccccCcc !!!!!68886676
Bra001325 836 C 8 ,,,,,.,, 68886676
Bra001325 841 A 6 ,$,.,,. BJJJJE
Bra001325 866 C 2 ,. HJ
And i want to extract all those lines which has a number 866
in the second column. When i use grep
command i am getting all the lines that contains the number that number
grep "866" test.txt
Bra001325 835 T 13 c$c$c$c$c$cccccCcc !!!!!68886676
Bra001325 836 C 8 ,,,,,.,, 68886676
Bra001325 866 C 2 ,. HJ
How can i match specific column with grep command?
Solution
Try doing this :
$ awk '$2 == 866' test.txt
No need to add {print}
, the default behaviour of awk
is to print on a true
condition.
with grep :
$ grep -P '^\S+\s+866\b' *
But awk can print filenames too & is quite more robust than grep here :
$ awk '$2 == 866{print FILENAME":"$0; nextfile}' *
Answered By - Gilles Quenot Answer Checked By - Dawn Plyler (WPSolving Volunteer)