[SOLVED] sed regexp find block of string in multiline block and remove string untill it end with space

Issue

I try to capture those blocks of strings and remove comment on them using regexp and sed. each block separated with space

some text here 
some text here 

# AppServer1:
#  name: ${AppServer1.name}
#  ip: ${AppServer1.ip}
   
some text here 
some text here 

# AppServer2:
#  name: ${AppServer1.name}
#  ip: ${AppServer1.ip}

some text here 
some text here 
   

I try with this regexp:

sed '/^AppServer1/I{:a; /^[[:blank:]]*$/!{s/.*#.*/&/; n; ba;} }' file

but it dos not effect the string

what im missing here to UN comment the full string to be :

AppServer1:
      name: ${AppServer1.name}
      ip: ${AppServer1.ip}

UPDATE After implementing @anubhava solution i notice that if the string is notice the extra "#" in between the blocks:

some text here 
some text here 

# AppServer1:
#  name: ${AppServer1.name}
#  ip: ${AppServer1.ip}
#   
# AppServer2:
#  name: ${AppServer1.name}
#  ip: ${AppServer1.ip}

some text here 
some text here 

And i like to remove only the comments of "AppServer1:" It will remove the comments also from "AppServer2:" and it will look like this :

AppServer1:
  name: ${AppServer1.name}
  ip: ${AppServer1.ip}
   
 AppServer2:
  name: ${AppServer1.name}
  ip: ${AppServer1.ip}

This can happen if someone by accident set extra "#" how can i add this OR condition in the regexp so if its blank line OR 1 # in the line dont continue to un comment ?

Solution

You may try this gnu-sed that doesn't require a blank line after commented lines that start with /# AppServer1/:

sed -E '/^#[[:blank:]]*AppServer1:/I, /^#?[[:blank:]]*$|^($|[^#])/ s/#[[:blank:]]?//' file

some text here
some text here

AppServer1:
 name: ${AppServer1.name}
 ip: ${AppServer1.ip}

# AppServer2:
#  name: ${AppServer1.name}
#  ip: ${AppServer1.ip}

some text here
some text here

Details:

• /^#[[:blank:]]*AppServer1:/I: Start range from a line that starts with # followed by 0 or more spaces and AppServer1: (ignore case)
• ,/^#?[[:blank:]]*$|^($|[^#])/: Range end with a line that just has # OR a line that doesn't have # at line start
• s/#[[:blank:]]?//: Removes first # followed by an optional space

Answered By - anubhava

Answer Checked By - Gilberto Lyons (WPSolving Admin)