[SOLVED] Floating point exception (core dumped) in C

Issue

While writing a C program and compiling it in fedora 32, I always get this message Floating point exception (core dumped) when I try to scan user's input from the terminal, and I don't know what i did wrong.

I put some printf functions in between to know where it stops, and what I found that scanf ("%i", &number); function doesn't read the input or save it correctly.

This is some of the code:

   #include <stdio.h>

int main (void)
{
    int number, constant, remain, remain1, mod, count, test;
    
    number = 0;
    mod = 1;
    count = 0;

    printf ("Enter a number to write: \n");
    scanf ("%i", &number);
    
    printf ("-1");
    
    constant = number;
    test = number;
    printf ("0");
    if (number < 0)
    {
        number = number * -1;
        printf ("-");
    }
    printf ("1");
    while (test != 0)
    {
        test /= 10;
        count++;
        printf ("%i", count);
    }
    printf ("2");
    for (int i = 1; i < count; i++)
    {
        mod = mod * 10; 
    }
    printf ("3");
    while (number != 0)
    {
        
        remain = number % mod;
        remain1 = constant - remain * mod;
        
        switch (remain)
        {
            case 0:
                printf ("Zero");
                break;
            case 1:
                printf ("One");
                break;
            case 2:
                printf ("Two");
                break;
            case 3:
                printf ("Three");
                break;
            case 4:
                printf ("Four");
                break;
            case 5:
                printf ("Five");
                break;
            case 6:
                printf ("Six");
                break;
            case 7:
                printf ("Seven");
                break;
            case 8:
                printf ("Eight");
                break;
            case 9:
                printf ("Nine");
                break;
        }

        remain = remain1;
        mod /= 10;
    }
    
        printf ("\n");
    
    return 0;
}

Solution

EDIT as for my original guess - it is division by zero

        if(!mod ) // add this if 
             {printf("Division by zero");exit(0);} //
        remain = number % mod;

---

Always check the result of the scanf. Yuo do not have any floating point opertions here, but probably you have division by zero somewhere in the code you did not show.

#include <stdio.h>

int main (void)
{
    int number, constant, remain, remain1, mod, count, test;
    
    number = 0;
    mod = 1;
    count = 0;

    printf ("Enter a number to write: \n");
    if(scanf ("%i", &number) != 1)
    {
        printf("scanf error\n");
    }
    else
    {    
        printf ("-1");
        
        constant = number;
        test = number;
        printf ("0");

        if (number < 0)
        {
            number = number * -1;
            printf ("-");
        }

        printf ("1");

        while (test != 0)
        {
            test /= 10;
            count++;
            printf ("%i", count);
        }

        printf ("2");

        for (int i = 1; i < count; i++)
        {
            mod = mod * 10; 
        }
    }
}

Here you have this function made simple:

char *digits[] = {"Zero","One","Two","Three","Four","Five","Six","Seven","Eight","Nine"};

void printWord(int x)
{
    int work = x;
    long val = 1;
    while(work)
    {
        val *= 10;
        work /= 10;
    }
    val /= 10;
    if(x < 0) printf("Minus");
    if(!x) val = 10;
    do
    {
        printf("%s", digits[abs(x / val)]);
        x %= val;
        val /= 10;
    }while(x);
}

int main (void)
{
    printWord(0);    
    return 0;
}

https://godbolt.org/z/q4oWqT

Answered By - 0___________

Answer Checked By - Terry (WPSolving Volunteer)