[SOLVED] How can I get what element is a value in an array from whether it matches a value?

Issue

I have a variable value which is 25. I want to search for that variable in an array with several elements and get the position in my array that matches the value of my variable. In this example, I should get that what I am looking for is position 3 as the 25 matches my variable. When it finds the value I want to store it in a variable so my result variable should be 3.

value=25
array=( 11 13 17 25 36 )
result=0

My idea is to go through the array with a for loop and if it finds the value it stores it in another variable. This is what I tried:

for i in ${array[@]}; do
   if [[ $i -eq $value ]]; then
      result=$i
   fi
done

But this returns 25 and not its position, how can I return its position in the array?

Solution

You can do something like this:

Assuming your array has only positive integers, declared result=-1 so that it prints -1 if no match is found.

Use a separate variable like index.

And increment its value by 1 as the loop progresses forward.

value=25
array=( 11 13 17 25 36 )
result=-1
index=0
for i in ${array[@]}; do
   if [[ $i -eq $value ]]; then
      result=$index
      
   fi
   index=$((index+1))
done

echo $result

Answered By - Novice

Answer Checked By - Willingham (WPSolving Volunteer)