Issue
How could I break a line using \n in read -p?
For example
read -p "Please Enter the percent [30 between 100]\n The value is Default = 80 :" scale_percent
I want \n to break a line but it doesn't work.
In echo I use -e and it breaks a line.
So I tried
read -ep
to break the line but it didn't break the line. How can I do that?
And could you also please give me a good manual for read -p on the Internet because I couldn't find a nice one without a confusing description.
Solution
You can do it this way:
read -p $'Please Enter the percent [30 between 100]\x0a The value is Default = 80 :' scale_percent
we use above syntax to insert hex values, we insert \x0a which is the hexadecimal value of the newline character (LF). You can use same syntax above with echo to produce new lines, eg:
echo $'One line\x0asecond line'
This is a feature of BASH 2, it is documented here, the $'' is used to translate all escape sequences inside it for its ascii transcription. So we could obtain the same result of example above, this way:
echo $'One line\nsecond line'
Answered By - Nelson Answer Checked By - Marie Seifert (WPSolving Admin)