[SOLVED] Ripgrep to only exclude a file in the root of the folder

Issue

If I have my folder like this:

dir:
    ├── 1.index1.html
    ├── 2.index2.html
    ├── 3.index3.html
    ├── a
    │   ├── 1.index1.html
    │   

How can I tell ripgrep in the command to exclude only the file index1.html in the root folder, but still searching the index1.html in folder a?

Solution

ripgrep has support for this, regardless of the globbing syntax that is support by your shell because its support is independent of the shell.

ripgrep's -g/--glob flag allows you to include or exclude files. And in particular, it follows the same semantics that gitignore uses (see man gitignore). This means that if you start a glob pattern with a /, then it will only match that specific path relative to where ripgrep is running. For example:

$ tree
.
├── a
│   └── index1.html
├── index1.html
├── index2.html
└── index3.html

1 directory, 4 files

$ rg --files
index1.html
a/index1.html
index2.html
index3.html

$ rg --files -g '!index1.html'
index2.html
index3.html

$ rg --files -g '!/index1.html'
index2.html
index3.html
a/index1.html

When using the -g flag, the ! means to ignore files matching that pattern. When we run rg --files -g '!index1.html', it will result in ignoring all files named index1.html. But if we use !/index1.html, then it will only ignore the top-level index1.html. Similarly, if we use !/a/index1.html, then it would only ignore that file:

$ rg --files -g '!/a/index1.html'
index1.html
index2.html
index3.html

ripgrep has more details about the -g/--glob flag in its guide.

Answered By - BurntSushi5

Answer Checked By - Willingham (WPSolving Volunteer)