Issue
here is my simple script prova.sh
:
#!/bin/bash
echo "\$# = [$#]"
echo "\$1 = [$1]"
if [ $# -ge 2 || $1="-h" ]
then
echo "#########################################################################"
echo -e "usage: $0 \t launches the program only"
echo -e " $0 -s\t shows the command fired and launches the program"
echo -e " $0 -so\t shows only the command fired"
echo -e " $0 -h\t shows this guide"
echo "#########################################################################"
exit 0
fi
command="ls -la"
if test "$1"="-so" || "$1"="-s"
then
echo "Fired command:"
echo $command
fi
if test "$1"!="-so"
then
$command
fi
here is the output:
$> ./prova.sh -h
$# = [1]
$1 = [-h]
./prova.sh: row 6 : [: "]" missing
./prova.sh: row6: -h=-h: command not found
Fired command:
ls -l
totale 4
-rwxrw-r--. 1 user user 632 20 lug 16.13 prova.sh
I expected just the help
Solution
you need to close every test using single brackets, the shell way, if [ $# -ge 2 ] || [ $1 = "-h" ]; then ...
this will fix it. If you still use single brackets way, is safe to enclose you variables with double quotes, so if they are empty, you are safe, like this if [ "$#" -ge 2 ] || [ "$1" = "-h" ]; then ...
or you can just put them inside a double bracket, and bash will handle this for you if [[ $# -ge 2 || $1 = "-h" ]]; then ...
Answered By - Kaneda Answer Checked By - Senaida (WPSolving Volunteer)