[SOLVED] How to print regexp matches using awk?

Issue

Is there a way to print a regexp match (but only the matching string) using awk command in shell?

Solution

Yes, in awk use the match() function and give it the optional array parameter (a in my example). When you do this, the 0-th element will be the part that matched the regex

$ echo "blah foo123bar blah" | awk '{match($2,"[a-z]+[0-9]+",a)}END{print a[0]}'
foo123

Answered By - SiegeX

Answer Checked By - David Goodson (WPSolving Volunteer)