[SOLVED] Saving variable with date in bash

Issue

The following call:

date -d `echo 20150430+1 | bc`

gives: date: invalid date ‘20150431’

and I am trying to save that output to the variable f without success:

f=`date -d \`echo "20150430+1" | bc\``

and

f=$(date -d $(echo 20150430+1 | bc))

They output an empty variable f, what am I doing wrong?

Any hints are appreciated,

PS: bash - 5.0-6ubuntu1.2

Solution

You need to capture stderr for example by redirecting it to stdout:

$ f=`date -d 20150431 2>&1`
$ echo $f
$ date: invalid date ‘20150431’`

Answered By - Allan Wind

Answer Checked By - Mary Flores (WPSolving Volunteer)