Issue
Run in bash the result is:
printf "%s\n" {a..Z}{a..Z}
bash: bad substitution: no closing "`" in `a
It works in an interesting way when run in zsh, even though zsh is usually sensitive to commands with unusual input characters.
printf "%s\n" {a..Z}{a..Z}
aa
a`
a_
a^
a]
a\
a[
aZ
`a
``
`_
`^
Is there a solution for this just under bash, so that you don't have to fiddle with zsh separately for every execution?
Solution
what could be the reason for this
Brace expansion happens before command substitution in Bash, while it's the other way around in Zsh.
and is there a solution?
I do not think so, nothing as clean as just running zsh like zsh -c 'printf "%s\0" {a..Z}{a..Z}' | while IFS= read -d '' -r a; do echo $a; done.
Answered By - KamilCuk Answer Checked By - Clifford M. (WPSolving Volunteer)
