Issue
I'm working on a bash script to rename automatically files on my Synology NAS.
I have a loop for the statement of the files and everything is ok until I want to make my script more efficient with regex.
I have several bits of code which are working like as expected:
filename="${filename//[-_.,\']/ }"
filename="${filename//[éèēěëê]/e}"
But I have this:
filename="${filename//t0/0}"
filename="${filename//t1/1}"
filename="${filename//t2/2}"
filename="${filename//t3/3}"
filename="${filename//t4/4}"
filename="${filename//t5/5}"
filename="${filename//t6/6}"
filename="${filename//t7/7}"
filename="${filename//t8/8}"
filename="${filename//t9/9}"
And, I would like to use captured group to have something like this:
filename="${filename//t([0-9]{1,2})/\1}"
filename="${filename//t([0-9]{1,2})/${BASH_REMATCH[1]}}"
I've been looking for a working syntax without success...
Solution
The shell's parameter expansion facility does not support regular expressions. But you can approximate it with something like
filename=$(sed 's/t\([0-9]\)/\1/g' <<<"$filename")
This will work regardless of whether the first digit is followed by additional digits or not, so dropping that requirement simplifies the code.
Answered By - tripleee Answer Checked By - Willingham (WPSolving Volunteer)