[SOLVED] How ignore error when use -Werror?

Issue

I have the follow test code test.c:

#include<stdio.h>
int *func()
{
    int i = 123;
    return &i;
}

int main()
{
    printf("%d\n", *func());
}

If I use the command compile it that is OK:

gcc test.c -o test

It will have the follow warning info:

warning: address of stack memory associated with local variable 'i'
  returned [-Wreturn-stack-address]
return &i;
        ^
1 warning generated.   

But it can output result: 123

If I use the command:

gcc -Werror test.c -o test

It will have the follow error info:

error: address of stack memory associated with local variable 'i'
  returned [-Werror,-Wreturn-stack-address]
return &i;
        ^
1 error generated. 

Now I want to use -Werror option, but I also want to ignore the address of stack memory associated with local variable 'i' warning, how should I do?

Solution

Most gcc warnings can be disabled by prefixing the name of the warning with no-, e.g. -Wno-return-stack-address.

That said, this is not something you want to ignore; returning pointers to stack variables is undefined behavior, and while it has semi-predictable results on most compilers, it's incredibly fragile; any function call at all, implicit or explicit, could stomp on the value that pointer is referencing.

Answered By - ShadowRanger

Answer Checked By - Cary Denson (WPSolving Admin)