Issue
I am doing a lab for my cs class and we are reverse engineering a "binary bomb". I am confused on a few assembler instructions. If anyone could explain what these do and how the work I would greatly appreciate it.
lea 0x10(%rbx), %rbp.
Im pretty sure rbx is supposed to hold the address of rbp, but im confused on the 0x10 argument.
mov 0x4(%rbx), %eax.
Same thing as above, don't understand what the 0x4 argument is.
Solution
These are offsets (0x10 = 16bytes and 0x4=4bytes) to the pointers in rbp and eax. Most likely iterating over elements in an array/vector.
Answered By - Gabriel Answer Checked By - Marilyn (WPSolving Volunteer)