Issue
I have a bash loop that I run to copy 2 files from the hpc to my local drive recursively over the processors and all the timesteps. On the hpc the timesteps are saved as
whereas the bash loop interprets it as
1.0 2.0 3.0
probably because of the 0.5 increment. Is there a way to get the $j to be changed to whole number (without the decimal) when running the script?
Script I use:
for i in $(seq 0 1 23)
do
mkdir Run1/processor$i
for j in $(seq 0 0.5 10);
do
mkdir Run1/processor$i/$j
scp -r [email protected]:/scratch/Run1/processor$i/$j/p Run1/processor$i/$j/
scp -r [email protected]:/scratch/Run1/processor$i/$j/U Run1/processor$i/$j/
done
done
Result:
scp: /scratch/Run1/processor0/1.0/p: No such file or directory
The correct directory that exists is
/scratch/Run1/processor0/1
Thanks!
Solution
well, yes!
but: Depending on what the end result is.
I will assume you want to floor the decimal number. I can think of 2 options:
- pipe the number to cut
- do a little bit of perl
for i in $(seq 0 1 23); do
for j in $(seq 0 0.5 10); do
# pipe to cut
echo /scratch/Run1/processor$i/$(echo $j | cut -f1 -d".")/U Run1/processor"$i/$j"/
# pipe to perl
echo /scratch/Run1/processor$i/$(echo $j | perl -nl -MPOSIX -e 'print floor($_);')/U Run1/processor"$i/$j"/
done
done
result:
...
/scratch/Run1/processor23/9/U Run1/processor23/9/
/scratch/Run1/processor23/9/U Run1/processor23/9.5/
/scratch/Run1/processor23/9/U Run1/processor23/9.5/
/scratch/Run1/processor23/10/U Run1/processor23/10/
/scratch/Run1/processor23/10/U Run1/processor23/10/
edit :
Experimented a litle, found another way:
echo /scratch/Run1/processor$i/${j%%.[[:digit:]]}/U Run1/processor"$i/$j"/
Answered By - Unamata Sanatarai Answer Checked By - David Marino (WPSolving Volunteer)