[SOLVED] How to launch a test on every lines of a file in bash?

Issue

I have a file that contains lines of the form:

(  1) 0 sec 730 usec
(  2) 0 sec 1 usec
(  3) 0 sec 1 usec
.
.
.
(998) 0 sec 1 usec
(999) 0 sec 0 usec

I would like to only display lines which contains more than 100 usec

I tried to use xargs but my attempts failed. I also tried to write a bash script with a while loop, storing my file inside an ARG variable. But I don't know how to make my while loop parse through every single lines of ARG...

How to do that in both ways please ? Thanks

Solution

Using awk

Match lines with 5 fields if the 4th field is greater than or equal to 100 or match lines with 6 fields if the 5th field is greater than or equal to 100.

awk '(NF==5 && $4>=100) || (NF==6 && $5>=100) {print $0}' src.dat 
(  1) 0 sec 730 usec

src.dat contents:

(  1) 0 sec 730 usec
(  2) 0 sec 1 usec
(  3) 0 sec 1 usec
.
.
.
(998) 0 sec 1 usec
(999) 0 sec 0 usec

Answered By - j_b

Answer Checked By - Mildred Charles (WPSolving Admin)